PLEASEEEEEE HELPPPPPPPPP
what are the zeros for this?
f(x) = 2x^2 + 6x + 2
1 answer:
Answer:
-3/2 ±1/2 sqrt(5) = x
Step-by-step explanation:
f(x) = 2x^2 + 6x + 2
Set the function equal to 0
0 = 2x^2 + 6x + 2
Factor out 2
0 = 2(x^2 + 3x + 1)
Divide by 2
0 = (x^2 + 3x + 1)
Subtract 1 from each side
-1 = x^2 +3x
Complete the square by dividing the x coefficient by 2 and then squaring
(3/2)^2 = 9/4
-1 +9/4 = x^2 +3x+9/4
-4/4+9/4 = (x+3/2) ^2
5/4 = (x+3/2) ^2
Taking the square root of each side
± sqrt(5/4) = sqrt( (x+3/2) ^2)
±1/2 sqrt(5) = (x+3/2)
Subtract 3/2 from each side
-3/2 ±1/2 sqrt(5) = x
You might be interested in
In linear change, the two variables keep increasing or decreasing at the same speed.
Are you trying to write an equation?
y-8=2(x-3)
y=2x-6+8
y=2x+2
Since it starts at 12 and is increasing by 5 each time, the 70th term will be;
12 + 5(70)
12 + 350
362
362 is the 70th term of the sequence.
Answer:
4
Step-by-step explanation:
(-3) * (8/-6)
3 * 8/6
3 * (2 * 4)/6
3 * (2 * 4)/(2 * 3)
3 * (4/3)
4
Answer:
Step-by-step explanation:
