This equation uses two properties of logarithms:


So you could take the ln from left and right hand side in the equation, and get:
(2-x)ln 3 = x ln 5
then
2 ln 3 - x ln 3 - x ln 5 = 0 =>
x(ln 3 + ln 5) = 2 ln 3
so x = 2 ln 3 / (ln3 + ln5)
Now using the 1st property you can say 2 ln 3 is ln 3² = ln9
and using the 2nd property you can say ln3 + ln5 = ln15
so x= ln9 / ln15
Where is the Question? or am i just blind
1 = 12, 2 = -6, 3 = -2, 4 = 3, 5 = 15, 6 = -13, 7 = -15, 8 = 11, 9 = -12, 10 = 0, 11 = -20
Divide the area into 6 portions and find the sum of each one to find the value of the final integral:
f(x)dx = 2(8+4)/2 + 1 (8+6)/2 + 2 (6+10)/2 + 1(10+10)/2 + 2 (10+12)/2 + 1 (12+16)/2
= 12 + 7 + 16 + 10 + 22 + 14 = 81 sq units
Answer:
The most likely solution sought is 13:
Beginning with 3: subtract 9, add 18, subtract 8, add 16, subtract 7, add 14, etc. Each time, reduce the number subtracted by one, and double that number to add.
So, beginning with 3: 3-9 = -6, -6+2(9) = 12, 12-8 = 4, 4+2(8) = 20, 20-7 = 13, etc.
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Step-by-step explanation: