All categories

3 years ago

Rationalise the denominator 1/√20

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

3 0

Answer:

1/10

Step-by-step explanation:

uf no me dij hi g go be h in go i

You might be interested in

ILL GIVE BRAINLEST, classify the triangle below with work please :)

Minchanka [31]

Answer:

A right triangle

Step-by-step explanation:

All interior angles in a triangle are equal to 180°.

x+x+2x = 180°

4x = 180°

x = 45°

So two of the angles are 45°, and the remaining angle is 45°×2 = 90° (a right angle).

7 0

2 years ago

EleoNora [17]

Answer:

ummmmmm peace out

Step-by-step explanation:

8 0

2 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Which expression is equivalent to (x^-4y/x^-9y^5)^-2

Nutka1998 [239]

Answer: simlify theexpression

y 12 x 10

7 0

2 years ago

jada walks up to a tank of water that can hold up to 10 gallons. When it is active, a drain empties water from the tank at a con

alexdok [17]

Answer:-2/3 gallon per minute

-2/3 gallon per minute

Step-by-step explanation:

6 0

3 years ago