1. Solubility
2. Heat 100g of water to 35 degrees C. Add 37 grams of mystery salt.
3. If all the salt dissolves, it's KCl. If not, it's KNO3.
The major ionic species present in aqueous solution of sodium sulfate is
2 Na+ and SO4^2-
<u><em>explanation</em></u>
When electrolyte dissolve in water they dissociate into ions.
There are two type of electrolyte that is strong and weak electrolyte.
Sodium sulfate is a strong electrolyte and therefore it dissociate completely into ions as below
Na2So4 → 2 Na+ (aq) + So4^2- (aq)
<span>According to Faraday's Law,
W = I t e / F
Where,
W = Amount deposited = ?
I = Current = 3 A
t = Time = 965 s
e = Chemical equivalence = 52/3 = 17.33
F = Faraday's Constant = 96500
Putting Values,
W = (3 × 965 × 17.33) ÷ 96500
W = (50170.35) ÷ 96500
W = 0.52 g
As we know,
Moles = mass ÷ M.mass
Putting values,
Moles = 0.52 ÷ 52
Moles = 0.01</span>
Answer:
0.7692 M ≅ 0.77 M.
Explanation:
- It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
<em>(MV) before dilution = (MV) after dilution.</em>
M before dilution = 2.0 M, V before dilution = 0.25 L.
M after dilution = ??? M, V after dilution = 0.25 L + 0.40 L = 0.65 L.
∴<em> M after dilution = (MV) before dilution/(V) after dilution</em> = (2.0 M)(0.25 L)/(0.65 L) =<em> 0.7692 M ≅ 0.77 M.</em>
Answer:
Mg(OH)2 + 2HCI = MgCI2 + 2H2O
Explanation:
Please correct me if I am wrong