For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
![\frac{V}{n} = k](https://tex.z-dn.net/?f=%20%5Cfrac%7BV%7D%7Bn%7D%20%3D%20k)
where V-volume, n-number of moles and k - constant
Therefore at 2 instances
![\frac{V1}{n1} = \frac{V2}{n2}](https://tex.z-dn.net/?f=%20%5Cfrac%7BV1%7D%7Bn1%7D%20%3D%20%20%5Cfrac%7BV2%7D%7Bn2%7D%20)
where V1 and n1 are for 1st instance
and V2 and n2 are for 2nd instance
therefore
![\frac{V1}{n1} = \frac{V2}{n2}](https://tex.z-dn.net/?f=%20%5Cfrac%7BV1%7D%7Bn1%7D%20%3D%20%5Cfrac%7BV2%7D%7Bn2%7D%20)
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated
![\frac{2.4}{3.7} = \frac{V2}{5.3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2.4%7D%7B3.7%7D%20%20%3D%20%5Cfrac%7BV2%7D%7B5.3%7D%20)
V2 = 2.4 x 5.3 / 3.7
= 3.4 L
Answer is 1st option 3.4 L
Not sure but i think living things adapt to their environment.
Adaptations are traits giving an organism an advantage in a certain environment. And variations of individuals is important for a healthy species. So i think adaptation might be the right answer because animal will try to adapt the certain environment. I hope this answer will help you.
<em>Answer</em><em>:</em>
Virtual images are always formed by convex mirrors and are formed by concave mirrors when the object is placed in front of F.
Explanation:
A concave mirror will only produce an upright image if the object is located in front of the focal Point.
Hope this helped. :)
Answer:
(2) Half of the active sites are occupied by substrate.
Explanation:
The Michaelis–Menten equation is the rate equation for a one-substrate enzyme-catalyzed reaction. It is an expression of the relationship between the initial velocity V₀ of an enzymatic reaction, the maximum velocity Vmax, and substrate concentration [S] which are all related through the Michaelis constant, Km.
Mathematically, the Michaelis–Menten equation is given as:
V₀ = Vmax[S]/Km + [S]
A special relationship exists between the Michaelis constant and substrate concentration when the enzyme is operating at half its maximum velocity, i.e. at V₀ = Vmax/2
substituting, Vmax/2 = V₀ in the Michaelis–Menten equation
Vmax/2 = Vmax[S]/Km + [S]
dividing through with Vmax
1/2 = [S]/Km + [S]
2[S] = Km + [S]
2[S] - [S] = Km
[S] = Km
Therefore, when the enzyme is operating at half its maximum velocity, i.e. when half of the active sites are occupied by substrate, [S] = Km