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ASHA 777 [7]
3 years ago
5

How does a catalyst work

Chemistry
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

For example:

C_{12}H_{22}O_{11}+11H_2SO_4\rightarrow 12C+11H_2SO_4+11H_2O

In this reaction H_2SO_4 acts as a catalyst.

Thus a catalyst increases the rate of reaction works by lowering the activation energy.

blondinia [14]3 years ago
3 0
It speeds up chemical reactions
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What is the capacity to do work known as?
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Answer:

it is energy

Explanation:

Energy is the ability to do work

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The reaction for the decomposition of ammonia (NH3) can be written as shown. If a student starts with 21.7 g of ammonia, how man
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3.88 grams will be released I believe
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Read 2 more answers
Work=? time=5s Power = 40w
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Answer:

200 J

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2 years ago
Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of alumin
Lerok [7]

<u>Answer:</u> The percentage yield of HF is 73.36 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ....(1)  

For calcium fluoride:

Given mass of calcium fluoride = 6.25 kg  = 6250 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium fluoride = 78.07 g/mol

Putting values in above equation, we get:  

\text{Moles of calcium fluoride}=\frac{6250g}{78.07g/mol}=80.05mol

For the given chemical reaction:

CaF_2+H_2SO_4\rightarrow CaSO_4+2HF

By Stoichiometry of the reaction:

1 mole of calcium fluoride produces 2 moles of hydrofluoric acid

So, 80.05 moles of calcium fluoride will produce = \frac{2}{1}\times 80.05=160.1mol of hydrofluoric acid

Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:

Moles of of hydrofluoric acid = 160.1 moles

Molar mass of hydrofluoric acid = 20.01 g/mol

Putting values in equation 1, we get:

160.1mol=\frac{\text{Theoretical yield of hydrofluoric acid}}{20.01g/mol}=3203.6g=3.20kg

To calculate the percentage yield of hydrofluoric acid, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of hydrofluoric acid = 2.35 kg

Theoretical yield of hydrofluoric acid = 3.20 kg

Putting values in above equation, we get:

\%\text{ yield of hydrofluoric acid}=\frac{2.35g}{3.20g}\times 100\\\\\% \text{yield of hydrofluoric acid}=73.36\%

Hence, the percentage yield of HF is 73.36 %

4 0
2 years ago
The mass ratio of H to O in water (H2O) is 1:8. What is the mass
svp [43]

Answer: 1:16

Explanation:

4 0
2 years ago
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