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ASHA 777 [7]
3 years ago
5

How does a catalyst work

Chemistry
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

For example:

C_{12}H_{22}O_{11}+11H_2SO_4\rightarrow 12C+11H_2SO_4+11H_2O

In this reaction H_2SO_4 acts as a catalyst.

Thus a catalyst increases the rate of reaction works by lowering the activation energy.

blondinia [14]3 years ago
3 0
It speeds up chemical reactions
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31.5 grams of an unknown substance is heated to 102.4 degrees Celsius and then placed into a calorimeter containing 103.5 grams
Alexxandr [17]
Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1) 

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

</span>Heat gained = Heat lost
mC(T2-T1) = - mC(T2-T1) 
31.5C (102.4 - 32.5) = 103.5(4.18)(32.5 - 24.5)
C = 1.57 J/C-g

Hope this helps.
5 0
3 years ago
The following are formed as white precipitates in solution except
aniked [119]

Answer:

A. Iron (III) hydroxide

Explanation:

Orange-brown or rust

6 0
3 years ago
Read 2 more answers
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq
ad-work [718]

Answer:

-75 cm^3/min

Explanation:

Given from Boyle's law;

PV=C

From product rule;

VdP/dt + PdV/dt = dC/dt

but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min

PdV/dt = dC/dt - VdP/dt

dV/dt = dC/dt - VdP/dt/ P

substituting values;

dV/dt = 0 - (500 * 30)/200

dV/dt = -75 cm^3/min

5 0
3 years ago
At what temperatures is a reaction that has a positive change in entropy
Setler [38]

Answer:

the answer is A

I made a chart for AP chem if you want to refer to it.

3 0
3 years ago
PLEASE HELP
dalvyx [7]

It has a -1 charge, so it would gain one!

5 0
3 years ago
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