Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
1) given 6x = 4x + 140
2) subtract 4x from both sides => 6x - 4x = 4x - 4x + 140
=> 2x = 140
3) divide both members by 2 => 2x / 2 = 140 / 2
=> x = 70
4) Answer: x = 70
Answer:
48 inch
Step-by-step explanation:
D bc it needs to have a y intercept of -1