Answer:
g CO2(g) = 264.06 g
Explanation:
∴ moles O2(g) = 6 mol
∴ mm CO2 = 44.01 g/mol
⇒ mol CO2(g) = ( 6 mol O2(g) )×( mol CO2(g) / mol O2(g) ) = 6 mol CO2(g)
⇒ mass CO2(g) = ( 6 mol CO2(g) )×( 44.01 g/mol ) = 264.06 g CO2(g)
Answer:
At the start of the process, the volume not occupied by the water is 2 m3
Explanation:
At the start of the process you have a half full tank. It means that also a half is empty (not occupied by water).
Since the volume is 4 m3, 2 m3 are full (occupied by water) and 2 m3 (not occupied by water).
The volume in time will be
![V(t)=V_0+(f_i-f_o)*t\\\\V(t) = 2 +(6.33/1000-3.25/1000)*t=2+0.00308*t \, \, [m3]](https://tex.z-dn.net/?f=V%28t%29%3DV_0%2B%28f_i-f_o%29%2At%5C%5C%5C%5CV%28t%29%20%3D%202%20%2B%286.33%2F1000-3.25%2F1000%29%2At%3D2%2B0.00308%2At%20%5C%2C%20%5C%2C%20%5Bm3%5D)
Answer:
what is that i connot understand your question
Explanation:
im sorry i connot answer your question
Answer:
electric is your answer :)
Explanation:
Edge STEM instruction/assignment perhaps???