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3 years ago

Think about the equation for kinetic energy, KE - mv?. Given that an increase in temperature increases kinetic

Chemistry

1 answer:

agasfer [191]3 years ago

3 0

Answer:

The correct answer would be - the speed of particles will increase and move faster.

Explanation:

As we know and also given that increase in temperature leads to an increase in kinetic energy that is used by particles and the speed of the particles move faster.

However, the mass of the particle is the main factor that is responsible for the speed of the particles and the temperature at which they are present. High temperatures and small particles lead to an increase in the speed of particles.

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Avery has a glass of pure water. She pours a tablespoon of sugar into the water to make it taste sweet.

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The first blank is a compound, second is a mixture

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You have 45.2 liters of SO2. This would be equal to

Andreas93 [3]

Answer:

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3 years ago

Write the balanced chemical equation for the reaction between aqueous sodium carbonate and

ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

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3 years ago

When is the Sun directly overhead in the continental United States?

astra-53 [7]

Answer:

Explanation:

The sun is directly overhead at noon on the equator on the first day of spring, and on the first day of fall. You would have to be less than 23.5 degrees above or below the equator to have the Sun pass directly overhead. Therefore, it never occurs in the continental US.

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An alkyne with the molecular formula C5H8 was reduced with H2 and Lindlar's catalyst. Hydroboration-oxidation of the resulting a

irinina [24]

Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.

The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.

When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.

Learn more: brainly.com/question/2510654

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