Answer:
a) 7.0.
b) Nickel sulfate hepta hydrate.
c) 280.83 g/mol.
d) 44.9%.
Explanation:
<u><em>a) What is the formula of the hydrate?</em></u>
The mass of the hydrated sample (NiSO₄.xH₂O) = 5.0 g,
The mass of the anhydrous salt (NiSO₄) = 2.755 g,
The mass of water = 5.0 g - 2.755 g = 2.245 g.
∴ no. of moles of water = mass/molar mass = (2.245 g)/(18.0 g/mol) = 0.1247 mol.
∴ no. of moles of anhydrous salt (NiSO₄) = mass/molar mass = (2.755 g)/(154.75 g/mol) = 0.0178 mol.
∴ water of crystallization in the sample (x) = no. of moles of water/no. of moles of anhydrous salt (NiSO₄) = (0.1247 mol)/(0.0178 mol) = 7.0.
<u><em>b) What is the full chemical name for the hydrate?</em></u>
The name of the salt (NiSO₄.7H₂O) is Nickel sulfate hepta hydrate.
<u><em>c) What is the molar mass of the hydrate? </em></u>
(NiSO₄.7H₂O)
The molar mass = molar mass of NiSO₄ + 7(molar mass of H₂O) = (154.75 g/mol) + 7(18.0 g/mol) = 280.83 g/mol.
<em><u>d) What is the mass % of water in the hydrate?</u></em>
The mass % of water = (mass of water)/(mass of hydrated sample) x 100 = (2.245 g)/(5.0 g) x 100 = 44.9%.
Answer:
Average atomic mass = 55.83 amu
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope, Fe-54:
% = 6 %
Mass = 53.94 amu
For second isotope, Fe-56:
% = 92 %
Mass = 55.93 amu
For third isotope, Fe-57:
% = 2 %
Mass = 56.94 amu
Thus,
<u>Average atomic mass = 55.83 amu</u>
A solution containing large amount of solute in comparison to solvent is concentrated. Meaning the solute's concentration is high. The answer to this question is letter "B" or "B. Concentrated". I hope this helps you on your assignment.
Answer:
W = +1624J
Explanation:
V1 = 33.0L
V2 = 61.0L
P = 58 atm
Work = force * distance (∇x)
Work = F.∇x
But force = pressure * area
F = P.A
Work = P.∇x.A
Work = P∇v
Work = P (V₂ - V₁)
Work = 58 * (61 - 33)
Work = 58 * 28
Work = 1624J
The work done is +1624J