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Alex787 [66]
4 years ago
7

What are different type of plastids explain them?​

Chemistry
1 answer:
BARSIC [14]4 years ago
6 0

Answer:

Explanation:

There are 3 types of plastids :-

1) Chloroplasts:- The green plastids which contain chlorophyll pigments for photosynthesis.

2) Chromoplasts:-The coloured plastids for pigment synthesis and storage.

3) Leucoplasts:- The colourless plastids for monoterpene synthesis found in non- photosynthetic parts of the plants.

They are of three types:-  

a) Amyloplasts- stores starch.

b) Proteinoplasts-  stores proteins.

c) Elaioplasts- stores fats and oils.

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ioda
Sodium is a very reactive metal. It is kept in kerosene to prevent it from coming in contact with oxygen and moisture. If this happens, it will react with the moisture present in air and form sodium hydroxide.
7 0
3 years ago
What is the term for the outer electron shell of an atom?
Musya8 [376]
The correct answer is D. Valence
4 0
3 years ago
A sample of methane collected when the temp was 30 C mmHg measures 398 mL. What would be the volume of the sample at -5 C and 61
Levart [38]
<h2>Question </h2>

A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure

<h2>Answer:</h2>

434.32mL

<h2>Explanation:</h2>

Using the combined gas law:

\frac{PV}{T} = k

Where;

P = Pressure

V = Volume

T = Temperature

k = constant.

It can be deduced that:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = k           ---------------------(i)

Where:

P₁ and P₂ are the initial and final pressures of the given gas

V₁ and V₂ are the initial and final volumes of the given gas

T₁ and T₂ are the initial and final temperatures of the gas.

<em>From the question:</em>

the gas is methane

P₁  = 760mmHg

P₂ = 616mmHg

V₁ = 398mL

V₂ = ?

T₁ = 30°C = (30 +273)K = 303K

T₂ = -5°C = (-5 +273)K = 268K

Substitute these values into equation (i) as follows;

\frac{760*398}{303} = \frac{616*V_2}{268}

Solve for V₂

V₂ = \frac{760*398*268}{616*303}

V₂ = 434.32mL

Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL

5 0
3 years ago
If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
gizmo_the_mogwai [7]
 The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95  (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
8 0
4 years ago
❗️❗️i need help with 10 pages of 11th grade chemistry questions. they are mostly mutiple choice. i really need this done I WILL
slamgirl [31]

Answer:

well you didnt post anything

Explanation:

6 0
3 years ago
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