Ask question

Ask question

All categories

2 years ago

8

Solving 8 problems per Minute, Fast Funn can finish his test in time. He was, however, working fast, solving 10 problems per min

ute. That is why he finished 6 minutes early. How many problems were on the text

1 answer:

ale4655 [162]2 years ago

7 0

The number of problems that were on the text was 240 problems.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the total number of problems that were on the text, y represent the time to be spent, hence:

y = x/8

Also:

y - 6 = x/10

x/8 - 6 = x/10

x = 240

The number of problems that were on the text was 240 problems.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

You might be interested in

What is the reciprocal of 3^-2 ?

weqwewe [10]

Answer:

1/3^2

Im trying to earn my brainliest..so if you don't mind :)

8 0

3 years ago

A sporting goods store offers 40% discount on all golf clubs. Rocco spent 20% of the money in his savings account on a golf putt

MatroZZZ [7]

Answer:

Rocco doesn't have enough money to buy the golf irons

Step-by-step explanation:

step 1

Find the rest of the money left in the savings account

using proportion

$\frac{\$48}{20\%}=\frac{x}{80\%}\\ \\x=48*80/20\\ \\x=\$192$

step 2

we know that

The set of golf irons has an original price of $359

Applying 40% discount

100%-40%=60%=60/100=0.60

after the discount the price will be

$0.60(\$359)=\$215.4$

$\$215.4> \$192$

therefore

Rocco doesn't have enough money to buy the golf irons

7 0

3 years ago

Help me with differentation and integration please!!

Marina86 [1]

Answer:

See below

Step-by-step explanation:

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

Recall

$\dfrac{d}{dx}\tan x=\sec^2$

Using the chain rule

$\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}$

such that $u = \tan x$

we can get a general formulation for

$y = \tan^n x$

Considering the power rule

$\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}$

we have

$\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x$

therefore,

$\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x$

Now, once

$\sec^2 x - 1= \tan^2x$

we have

$3\tan^2x \sec^2x = 3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x$

Hence, we showed

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

================================================

For the integration,

$\int \sec^4 x\, dx$

considering the previous part, we will use the identity

$\boxed{\sec^2 x - 1= \tan^2x}$

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx$

Considering $u = \tan x$

and then $du=\sec^2x\ dx$

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0

3 years ago

A child born today will see more than _____________ advertisements in their life.

Ymorist [56]

The answer would be 1 million because if the average person lives to be 70 multiply that by 2000 and you get 51100000 so I would say that total is closer to 1 million then it is to 3 billion

5 0

4 years ago

in cooking 1 drop equals 1/6 of dash . if a recipe calls for 2/3 of a dash , how many drops would that be?

Aleks [24]

1 / (1/6) = x / (2/3)...1 drop to 1/6 dash = x drops to 2/3 dash
cross multiply
(1/6)(x) = (1)(2/3)
1/6x = 2/3
x = 2/3 * 6
x = 12/3 = 4 drops <==

7 0

3 years ago