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enyata [817]
2 years ago
8

Solving 8 problems per Minute, Fast Funn can finish his test in time. He was, however, working fast, solving 10 problems per min

ute. That is why he finished 6 minutes early. How many problems were on the text
Mathematics
1 answer:
ale4655 [162]2 years ago
7 0

The number of problems that were on the text was 240 problems.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the total number of problems that were on the text, y represent the time to be spent, hence:

y = x/8

Also:

y - 6 = x/10

x/8 - 6 = x/10

x = 240

The number of problems that were on the text was 240 problems.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

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I’ll mark brainliest what’s 1228822882-1228822882?
xxMikexx [17]

0

Subtract

Answer is 0

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4 0
3 years ago
Read 2 more answers
Find the slope of each line. <br> 2
ratelena [41]

Answer: m=3/2

Step-by-step explanation: the slope starts from the left side and the line is going up meaning its positive, now the line is going up by 3s and to the right in 2s.

5 0
3 years ago
2c + 4d<br> C=8<br> D=-5<br> Please help
Dahasolnce [82]

Answer:

2c+4d

if c=8 and D=5,

2(8)+4(5)

16+20

=36

Step-by-step explanation:

5 0
3 years ago
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The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a
kobusy [5.1K]

Answer: C=270x+2200

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose C=mx+a is the linear equation defining the cost per student after x years

Substitute the value for 1978

\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200

After 30 years it becomes

\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270

Thus, the linear equation becomes

\Rightarrow C=270x+2200

6 0
3 years ago
A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta
Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.

It is provided that the family has invested in <em>n</em> = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39

Now the lowest 80% of the amount invested can be represented as follows:

P(\bar X

The value of <em>z</em> is 0.84.

*Use a <em>z</em>-table.

Compute the value of the mean amount invested as follows:

\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}

   =225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0
3 years ago
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