We have been given that in ΔBCD, the measure of ∠D=90°, the measure of ∠C=42°, and CD = 7.5 feet. We are asked to find the length of DB to nearest tenth of foot.
First of all, we will draw a right triangle using our given information.
We can see from the attachment that DB is opposite side to angle C and CD is adjacent side to angle.
We know that tangent relates opposite side of right triangle to adjacent side of right triangle.
Therefore, the length of DB is approximately 6.8 feet.
P=6 - value .01
d=12 or 2*p - value .1
n=3 - value .05
q=12 or 4*n - value .25
Multiply each denomination's value by how many she had.
(6*.01)+(12*.1)+(3*.05)+(12*.25)
.06+1.20+.15+3.00
$4.41
Answer:
I believe the answer is 84 centimeters.
Step-by-step explanation:
If the wheel is 5.6 centimeters in diameter, the car is traveling 5.6 centimeters per spin of the wheels. Therefore, you do the equation, 5.6 * 15 and get 84.
Answer:-12+6y
Step-by-step explanation:
Since the 12 is a negative and the 6y is a positive you can switch it around.