The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
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How long would it take $120/hr to add up to $1000?
Divide $1000 by $120/hr:
$1000
----------- = 8 1/3 hours, or 8 hours 20 minutes.
$120/hr
Answer:
a) 4,096
b) 0.000244
Step-by-step explanation:
a)
By the Fundamental rule of counting, there are
4*4*4*4*4*4 = 4,096
ways of forming six-digit arrangements where each position has 4 possibilities (1 to 4)
b)
The probability of entering the correct code on the first try, assuming that the owner does not remember the code is
1/4096 = 0.000244
Answer:
The answer is 44.66
Step-by-step explanation:
Multiply 58 by 0.23. This will give you 13.34. Next, you subtract this from 58 to get your original price.
If it's a square then sides equal to around 12-13 meters
