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arlik [135]
3 years ago
8

Find the value of x

Mathematics
1 answer:
marin [14]3 years ago
5 0

Answer:

x=14

Step-by-step explanation:

The given triangle is a right triangle, meaning it is a triangle with a right angle, this is indicated by the box around one of the angles. When given a right triangle, one can use the right triangle trigonometric ratios. These ratios describe the relationship between an angle in a right triangle, and the sides in a right triangle. Such ratios are as follows,

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Bear in mind that the way one names the sides, in the sense of (opposite or adjacent) will change based on the angle one uses to describe the triangle. However, the hypotenuse is the same no matter the angle, as the hypotenuse is the side opposite the right angle.

In this case, one is given one of the angles, and the side opposite the angle. One is asked to find the hypotenuse of the triangle. One can use the sine (sin) ratio to achieve this.

sin(\theta)=\frac{opposite}{hypotenuse}

Substitute,

sin(30)=\frac{7}{x}

Inverse operations,

x=\frac{7}{sin(30)}

Simplify,

x=14

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Pls help fastBelow!!!!
julsineya [31]

So the scale is 3/4 cm for every 6 meters

So if you have 8 cm, we want to find the dimension of the actual wall

convert cm to meters

0.75 cm = 0.0075 meters

8 cm = 0.08 meters

\frac{0.0075}{6} = \frac{0.08}{x}

Cross Multiply

0.0075x = 0.48

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6 0
3 years ago
4+ (b+0) + =<br><br><br><br> i need help guys
EleoNora [17]
Easy dude.
This simplifies to 4+b

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4 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
Which of these pairs are equal?
AVprozaik [17]

Answer: sin 33° and cos 57°

Step-by-step explanation:

4 0
3 years ago
You have $80. Jeans costs $29 and shirts $12. Mom told you to buy one pair of jeans and use the rest of the money to buy shirts.
SIZIF [17.4K]
You can buy 4 shirts because you bought one pair of jean (80 - 29 = 51) and so with the leftover money you could buy 4 shirts because (12 x 4 = 48) and then you'd have a leftover 3 dollars. 
8 0
3 years ago
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