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sergiy2304 [10]
3 years ago
5

What is 5(8)-2(15-8)​

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

This is the answer of your question. ☺☺

Step-by-step explanation:

40 -2*7

40 -14

26

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Factor. 2v^2-11v-63
Tatiana [17]

Answer:

  (2v +7)(v -9)

Step-by-step explanation:

Factors of 2·(-63) = -126 that have a sum of -11 are 7 and -18, so we can rewrite the middle term to -18v+7v. Then we can factor by grouping.

  2v^2 -18v +7v -63 = 2v(v -9) +7(v -9)

  = (2v +7)(v -9)

5 0
3 years ago
I need it ASAP! Melanie had bags of sand for a sandbox. The sandbox needs bags of sand to fill it.
Orlov [11]
 <span>Melanie had 2 1/2 bags of sand for a sandbox. The sandbox needs 3 1/4 bags of sand to fill it. Melanie said she still needs 3/4 of a bag to fill it. Is that answer reasonable?
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3.25 or 3 and 1/4 - 2.25 or 2 and 1/2= .75 or 3/4</span> so the answer is C.
7 0
3 years ago
What are the solutions to x^2-5x+3=0?
Viktor [21]

Answer:

Step-by-step explanation:

You need to use the quadratic equation

x =  \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

Givens

  • a = 1
  • b = - 5
  • c = 3

x = \frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2} \\

x =( 5 +/- sqrt(25 - 12) ) / 2

x = (5 +/- sqrt(13) )/2

x = (5 + sqrt(13) / 2

x = 4.303  rounded

x = (5 - sqrt(13) ) /2

x = .6972

4 0
3 years ago
Find all values of c such that 5c - 4 = 7 - 4-c/3
Marina CMI [18]
Hey there!

5c - 4 = 7 - \dfrac{4 - c}{3} \\ 15c - 12 = 21 - 4 + c \\ 14c = 29 \\ c = 2 \dfrac{1}{14}

Hope this helps. - M
5 0
3 years ago
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Marco is making a kite, using sticks for its diagonals. One stick is 2 feet long and the other is 3 feet long. How much material
Marat540 [252]

Answer:

Marco will need 3\ ft^{2} of material to make the kite

Step-by-step explanation:

we know that

To know how much material Marco will need to make the kite, the area must be calculated.

Remember that the area of the kite is equal to

A=\frac{1}{2}[d1*d2]

where

d1 and d2 are the diagonals of the kite

we have

d1=2\ ft

d2=3\ ft

substitute

A=\frac{1}{2}[2*3]=3\ ft^{2}

3 0
3 years ago
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