Square root of 100 = 10 cm. Next, 10*2 = 20^2 = 400 ft. Next, convert cm into ft, which would make 100 into about 3.3 ft. The ratio would then be about 3/400. Does that help?
90÷5=18 which means she makes $18 every hour.
Answer= $18
- Find the surface area when r is 8 inches and h is 8 inches.
A. 160π in²
B. 154π in²
C. 288π in²
D. 256π in² ☑
We are given –
⇢Radius of cylinder , r = 8 inches
⇢ Height of cylinder, h = 8 inches.
We are asked to find surface area of the given cylinder.
Formula to find the surface cylinder given by –

Now, Substitute given values –






- Henceforth,Option D is the correct answer.
?????????????????????/ us a calculator to add up all the nub.
The opposite angles of a parallelogram are congruent, so you have to set the values of each angle equal to each other and solve for x.
(10x-19)° = (7x+23)°
-7x -7x
3x-19 = 23
+19 +19
3x = 43
÷3 ÷3
x = 43
Then, substitute the value of x back into the equations.
(10x-19)°
(10(14)-19)°
(140-19)°
121°
(7x+23)°
(7(14)+23)°
(98+23)°
121°