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levacccp [35]
3 years ago
11

name the algebraic property demonstrated in the example below: if x = 3 and 3 = y, then x = y. a) commutative property of additi

on b) associative property of addition c) transitive property d) symmetric property
Mathematics
1 answer:
Ratling [72]3 years ago
7 0
<span>if x = 3 and 3 = y, then x = y is the transitive property.</span>
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im confused with this please help i dont get any answers, it is about rounding, not sure why this question is confused
Shkiper50 [21]

Step-by-step explanation:

<u>13,789:</u>

Tens: 13,790

Hundreds: 13,800

Thousands: 14,000

Ten thousands: 10,000

<u>24,173:</u>

Tens: 24,170

Hundreds: 24,200

Thousands: 24,000

Ten thousands: 20,000

<u>861,630:</u>

Tens: 861,630

Hundreds: 861,600

Thousands: 862,000

Ten thousands: 860,000

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2 years ago
Round 3,047 to the nearest hundredth
Aleksandr-060686 [28]
It should be 3,000
------------------------
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3 years ago
WILL GIVE A BRAINLIEST!! PLEASE HELP!!
OLga [1]
The domain of the function is the set of all x's that are suitable for the given equation. In the problem, we are asked to determine the equation with the most restricted domain. Option A can have x from negative infinity to positive infinity as well as option B and option D. OPtion C can only have x equal to zero and all positive numbers. Hence the answer is C. hope that helped
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3 years ago
Read 2 more answers
I am confused on how to do this.​
Charra [1.4K]
The answer is A.....
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3 years ago
Determine the slope of the line that passes through each pair of points.
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1.)\\\\(5,1) \  \ and  \ \ (2,7)\\\\First \  find \ the \  slope \ of \ the \ line \ thru \  the \  points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} }   \\ \\m=\frac{ 7-1}{2-5} =  \frac{6}{-3}=-2 \\ \\   Use  \  point \  form  \ of  \ a \  line\  with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=-2 , \ \x_{1}=5, \ \ y_{1}=1 \\ \\y-1 = -2(x-5 ) \\\\y=-2x+10+1 \\ \\y=-2x+11


2.)\\\\(5,3)\ \ and \ \ (-2,3)\\\\First \  find \ the \  slope \ of \ the \ line \ thru \  the \  points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} }   \\ \\m=\frac{  3-3}{-2-5} =  \frac{0}{-7}=0\\ \\   Use  \  point \  form  \ of  \ a \  line\  with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=0 , \ \x_{1}=5, \ \ y_{1}=3 \\ \\y-3 = 0\cdot (x-5 ) \\\\y-3=0 \\ \\y=3
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