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3 years ago

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name the algebraic property demonstrated in the example below: if x = 3 and 3 = y, then x = y. a) commutative property of additi

on b) associative property of addition c) transitive property d) symmetric property

1 answer:

Ratling [72]3 years ago

7 0

<span>if x = 3 and 3 = y, then x = y is the transitive property.</span>

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∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure

exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

so

$z=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$y=40\ units$

substitute

$\frac{1}{10}=\frac{x}{40}$

solve for x

$x=(40)\frac{1}{10}$

$x=4\ units$

therefore

The length of the longest side of ∆ABC is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

$z^{2}=\frac{x}{y}$

we have

$z=\frac{1}{10}$

so

$z^2=(\frac{1}{10})^2$

$z^2=\frac{1}{100}$

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

3 0

2 years ago

If z = f(x, y), where f is differentiable, and x = g(t) y = h(t) g(9) = 6 h(9) = 4 g' (9) = −6 h' (9) = 4 fx(6, 4) = 9 fy(6, 4)

horsena [70]

Answer:

dz / dt = -50

Step-by-step explanation:

To solve the chain rule must apply, we have all the necessary values to make the calculation, as follows:

using the chain rule, we find:

dz / dt = (∂z / ∂x) * (∂x / ∂t) + (∂z / ∂y) * (∂y / ∂t)

Evaluating when t = 9, we have to:

fx (6, 4) * g '(9) + fy (6, 4) * h '(9)

We know that g '(9) = −6; h '(9) = 4; fx (6, 4) = 9; fy (6, 4) = 1

Replacing:

(9 * -6) + (1 * 4) = -50

Por lo tanto dz / dt = -50

6 0

3 years ago

POR FAVORRRRRRR NECESITO RÁPIDO LA RESPUESTA<br><br> 3m (4x-5) - 20x + 25

nalin [4]

Answer:

12mx-15m-20x+25 Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Help with this question!

zheka24 [161]

Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)

7 0

3 years ago

If the total area of a picture measuring 10 inches by 12 inches plus a matting of uniform width surrounding the picture is 224 s

ELEN [110]

Let
x-----------> <span>uniform width surrounding the picture

we know that
(10+2x)*(12+2x)=224-----> 120+20x+24x+4x</span>²=224
4x²+44x+120-224=0
4x²+44x-104=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
x=2 in

the answer is
2 inches

4 0

3 years ago