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Leno4ka [110]
3 years ago
9

Simplify radicals please

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0
Answer:

-24x^5 y^2 z^8 /3yz

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What is (4/9-7/15) divided by 13/10
Rufina [12.5K]
First find least common denominator to subtract.
9=(3)×3
15=(3)×5
3×3×5=45 is lcd
4/9=20/45
7/15=21/45
(20/45-21/45)=(20-21)/45=-1/45
-1/45÷13/10
multiply by reciprocal instead of dividing
-1/45×10/13=(1×10)/(45×13)

-10/585
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3 years ago
Giving that 1 kilogram = 2.2 pounds, convert the following by setting up a portion​
Reptile [31]

Answer:you didnt add the whole thing what is the following??

Step-by-step explanation:

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3 years ago
KLMN and PQRS are similar trapezoids. which side of PQRS corresponds to LM​
zhuklara [117]

Answer:

QR

Step-by-step explanation:

K<u>LM</u>N is in the same spot as P<u>QR</u>S

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3 years ago
Read 2 more answers
Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each.
kakasveta [241]
Here is the inequality you can enumerate:

5x >= 200, this means the money you sold for cakes must be larger or equal to your goal

x <= 100, this means you cannot sell more than 100 cakes, because you only have 100 cakes

Solve for them, you will get: 40 <= x <= 100
5 0
4 years ago
When fritz drives to work his trip takes 40 ​minutes, but when he takes the train it takes 30 minutes. find the distance fritz t
sweet-ann [11.9K]
Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = \frac{2}{3}s
distance the train travel = \frac{1}{2}(s+15)

The question: Assume that the train travels the same distance as the car
==> \frac{2}{3}s = \frac{1}{2}(s+15)
==> \frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}
==> \frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}
==> \frac{1}{6}s = \frac{15}{2}
==> \frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}
==> s = 45 
Now we know that Fritz drive at 45 mph, 
distance = \frac{2}{3} * 45 = 30 miles
3 0
4 years ago
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