Ruby is taking a road trip to see her parents. She drives 114 hours which covers 18 of her trip. How many hours will it take her
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Answer:
see below
Step-by-step explanation:
Add 4 to find the solution:
z ≤ 7
The value 7 is included in the solution set, so there will be a solid dot at that point. Numbers less than 7 are also included in the solution set, so the number line will be shaded to the left of that solid dot.
The value of mean, standard deviation and interval from the method of tree ring dating is 1273 AD, 37 years, [1250,1296].
According to the statement
we have to find that the standard deviation, mean and the intervals from the given data.
So, According to the given data from the method of tree ring dating
The value of mean is
x-bar = (1271 + 1208 + 1229 + 1299 + 1268 + 1316 + 1275 + 1317 + 1275) / 9 = x-bar = 1273 AD
And now we find standard deviation :
s = √∑(xi - x-bar) / (N - 1)
∑(xi - x-bar)^2 = (1271 - 1273)2 + (1208 - 1273)2 + (1229 - 1273)2 + ... + (1275 - 1273)2
∑(xi - x-bar)^2 = (-2)2 + (-65)2 + (-44)2 + ... + (2)2
∑(xi - x-bar)^2 = 4 + 4225 + 1936 + 676 + 25 + 1849 + 4 1936 + 4
∑(xi - x-bar)^2 = 10,659
Now,
s^2 = 10659/8 = 1332
s = 37 years
So, standard deviation is 37 years.
We need the t-distribution table since the standard deviation is unknown. Therefore, our degrees of freedom is 9 - 1 = 8 and the critical value is 1.860. Set up the confidence interval for the mean:
[x-bar ± t*(s/√n)] = [1273 ± 1.860*(37/√9)]
[x-bar ± t*(s/√n)] = [1250,1296]
So, The value of mean, standard deviation and interval from the method of tree ring dating is 1273 AD, 37 years, [1250,1296].
Learn more about method of tree ring dating here
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Question:
The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
For more data please see the image below.
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Caitlin has 27 $5 bills and 54 $10 bills.
Step-by-step explanation:
Given,
Worth of $5 and $10 bills = $675
Let,
Number of $5 bills = x
Number of $10 bills = y
According to given statement;
5x+10y=675 Eqn 1
She has twice as many $10 bills as $5 bills.
y=2x Eqn 2
Putting value of y from Eqn 2 in Eqn 1
Dividing both sides by 25
Putting x=27 in Eqn 2
Caitlin has 27 $5 bills and 54 $10 bills.
Keywords: linear equation, substitution method
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