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3 years ago

Help asap no trolls pls!!

Mathematics

2 answers:

sineoko [7]3 years ago

5 0

Answer:

Step-by-step explanation:

GREYUIT [131]3 years ago

3 0

Answer:

Step-by-step explanation:

Sum of angles in a triangle = 180°

66c + 40c +74c = 180°

106c + 74c =180

180c = 180

c=1

Side v is the largest

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Solve for x and y pls

Paraphin [41]

X is a 90 degree angle so x equals half of 90 which is 45
X= 45
Since x is 45 the other angle on the other side is 45
Every triangle equals 180 so you take 45+45 to get 90 and subtract that from 180 and get 90
Y= 90
hope this helped ask questions

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3 years ago

Solve for x describe and correct the error in the image

marin [14]

Answer:140 over 3

Step-by-step explanation: i got that answer but i dont think its the right

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3 years ago

What is decending order

ludmilkaskok [199]

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2 years ago

2. A rope is thrown over a beam, and one end is tied to a 300 N bundle of lumber. You pull the free end of the rope 2 m with a f

bonufazy [111]

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3 years ago

Which of the following shows that EFGH is a parallelogram for y=7 and z=9?

Anna35 [415]

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Explanation:

Option A: $m \angle E=m \angle F=60^{\circ}$ and $m \angle G=120^{\circ}$ so $\angle G$ is supplementary to both $\angle E$ and $\angle F$ , so EFGH is a parallelogram

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we get, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Thus, $m \angle E\neq m \angle F$ because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Hence, Option B is the correct answer.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

To determine the angles, let us substitute $z=9$ in $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$

Thus, $m \angle F=m \angle G=120^{\circ}$

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Adding the angles E and G, we have,

$m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}$

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

3 0

3 years ago