Find the difference of the two expressions. (2/3+2)−(1/3−4)<br> •−2<br> •+6<br> •1/3−2<br> •1/3+6

The sales tax is $1002.80 on an automobile purchase of $21800. what is the sales tax rate?

AfilCa [17]

Answer:

21.7391%

Step-by-step explanation:

21800/1002.80

7 0

2 years ago

What constant do you need to add to each quadratic to complete the square?

babunello [35]

Answer:

1. 4

2. 16

3. 9

Step-by-step explanation:

Completing the square requires a quadratic in $ax^2+bx=c$ form. Once in this form, calculate $(\frac{b}{2})^2$ .

1. $(\frac{b}{2})^2=(\frac{-4}{2})^2=4$

2. $(\frac{b}{2})^2=(\frac{-8}{2})^2=16$

3. Requires you divide everything by 3 first.

$\frac{3x^2+18x}{3} =\frac{249}{3} \\x^2+6x=81$

$(\frac{b}{2})^2=(\frac{6}{2})^2=9$

6 0

2 years ago

Please I need help on this test

vovangra [49]

Answer:

$y = \frac{3}{2} x$

$y = 3$

$y - intercept = - 3$

$slope = - 1$

Step-by-step explanation:

Hope this helps!

✧◝(⁰▿⁰)◜✧

6 0

2 years ago

Savannah runs a day care center. Of the 12 children at the day care center, 3 of them are

sertanlavr [38]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

3 out of 12 children at the day care center are 5-year-olds. So, the probability of a randomly selected child being a five-year old is $\frac{3}{12}$ , or $\frac{1}{4}$ .

6 0

2 years ago

3 questions in 1

MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0

2 years ago

Find the difference of the two expressions. (2/3+2)−(1/3−4) •−2 •+6 •1/3−2 •1/3+6