Answer:
1/8
Step-by-step explanation:
kickball, volleyball, soccer, or free play = 4 choices
upper field or the lower field. = 2 choices
They have a total of 4*2 = 8 choices
We want 1 choice
That is 1 out of the 8 choices
1/8
That is what it looks like
4096 ways : 8 candy toppings plus 4 fruit toppings is 12. Then 2^12 (2 different types of toppings and the 12 of total toppings) = 4096
Answer:
c
Step-by-step explanation:
cus that's the answer lol
we are given
first term is
![a_1=42](https://tex.z-dn.net/?f=%20a_1%3D42%20)
common ratio is
![r=\frac{3}{4}](https://tex.z-dn.net/?f=%20r%3D%5Cfrac%7B3%7D%7B4%7D%20%20)
now, we can find nth term
![a_i=a_1(r)^{i-1}](https://tex.z-dn.net/?f=%20a_i%3Da_1%28r%29%5E%7Bi-1%7D%20)
now, we can plug values
![a_i=42(\frac{3}{4})^{i-1}](https://tex.z-dn.net/?f=%20a_i%3D42%28%5Cfrac%7B3%7D%7B4%7D%29%5E%7Bi-1%7D%20)
now, we can write in sigma form
![sum=\sum _{i=1}^{\infty }\:42(\frac{3}{4})^{i-1}](https://tex.z-dn.net/?f=%20sum%3D%5Csum%20_%7Bi%3D1%7D%5E%7B%5Cinfty%20%7D%5C%3A42%28%5Cfrac%7B3%7D%7B4%7D%29%5E%7Bi-1%7D%20)
now, we can find sum
we can use formula
![sum=\frac{a}{1-r}](https://tex.z-dn.net/?f=%20sum%3D%5Cfrac%7Ba%7D%7B1-r%7D%20%20)
now, we can plug values
we get
![sum=\frac{42}{1-\frac{3}{4}}](https://tex.z-dn.net/?f=%20sum%3D%5Cfrac%7B42%7D%7B1-%5Cfrac%7B3%7D%7B4%7D%7D%20%20)
![sum=168](https://tex.z-dn.net/?f=%20sum%3D168%20%20)
so, option-D.................Answer