Answer:
The probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Step-by-step explanation:
Given : Cherry trees in a certain orchard have heights that are normally distributed with
inches and
inches.
To find : What is the probability that a randomly chosen tree is greater than 140 inches?
Solution :
Mean -
inches
Standard deviation -
inches
The z-score formula is given by, ![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Now,
![P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cfrac%7B140-%5Cmu%7D%7B%5Csigma%7D%29)
![P(X>140)=P(Z>\frac{140-112}{14})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E%5Cfrac%7B140-112%7D%7B14%7D%29)
![P(X>140)=P(Z>\frac{28}{14})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E%5Cfrac%7B28%7D%7B14%7D%29)
![P(X>140)=P(Z>2)](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E2%29)
![P(X>140)=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E140%29%3D1-P%28Z%3C2%29)
The Z-score value we get is from the Z-table,
![P(X>140)=1-0.9772](https://tex.z-dn.net/?f=P%28X%3E140%29%3D1-0.9772)
![P(X>140)=0.0228](https://tex.z-dn.net/?f=P%28X%3E140%29%3D0.0228)
Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Answer:
there is one solution in my opinion
Step-by-step explanation:
In getting the x, you must first convert the said data in to a slope intercept form and the formula for it is y = mx+b so the slope is 7/16 while the y is 3.5. In that data its self you can came up with the equation of 3.5 = 7/16x + 0 and the value of X would be 8. I hope you are satisfied with my answer
Depends how many times pink is on the spinner you put the number of pink spaces there is at the top out of seven for example a fraction 3/7