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iren2701 [21]
3 years ago
7

The history museum is hosting a special exhibition on history of flight. The admission ticket for each adult costs $3 and the ad

mission ticket for each child costs $2. On the opening day of the exhibition, 60 tickets were sold for a total of $160. How many adults visited the special exhibition?
Mathematics
2 answers:
QveST [7]3 years ago
5 0

Answer:

32-40

Step-by-step explanation:

Since it does not give us any specifications as to the exact numbers, we can assume that the amount of adults ranges from 32 to 40, as these are the only numbers that are whole when divided. Obviously, we can't have 24.3333 of a person, so we have our range of answers.

SVEN [57.7K]3 years ago
3 0

Use simultaneous equation for this problem

y= number of adults

x = number of children

3y + 2x = 160

y + x = 60

then we double the second equation

3y + 2x = 160

2y + 2x = 120

we cancel x by elimination

3y - 2y = 160 - 120

y = 40

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The formula=A+2lh+2wh gives surface area a. Of a rectangler solid with length, width, and height, L,W, and H, respectively solve
iogann1982 [59]

Answer:

l= \frac{A}{2h} -w

Step-by-step explanation:

The question is not correct (particularly the expression for the area)

 A=2lh+2wh

Now we are expected to solve for l, that is we are going to make l subject of the formula, we have

let us take the second term on the RHS to the LHS

A-2wh= 2lh

we can now divide both sides by 2h we have

\frac{A-2wh}{2h} = l\\\\l=\frac{A}{2h} -\frac{2wh}{2h} \\\\l= \frac{A}{2h} -w

hence the expression for the length is  l= \frac{A}{2h} -w

6 0
3 years ago
The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
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