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2 years ago

A bucket holds 2 liters of water. How many milliliters of water can the bucket hold?

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

7 0

The number of milliliters of water that the bucket can hold is 2000 milliliters.

First and foremost, it's important to know that 1000 milliliters is thesame thing as 1 liter.

Therefore, for one to get the number of milliliters in 2 liters, one will have to multiply 1000 milliliters by 2. This will be:

= 1000 milliliters × 2

= 2000 milliliters

Also, you can do the same for other figures too e.g. for 5 liters will be:

= 5 × 1000 milliliters

= 5000 milliliters.

In conclusion, the number of milliliters of water that the bucket can hold is 2000 milliliters

Read related link on:

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Answer:

306

Step-by-step explanation:

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3 years ago

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ehidna [41]

Answer:

E. y - 4 = 6(x+2) is the answer

slope:

m = -8-4/-4+2 = 6

Formula:

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Step-by-step explanation:

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3 years ago

ANSWER ASAP

Nadusha1986 [10]

Y=mx+b
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3 years ago

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UkoKoshka [18]

Answer:

b. 896

Step-by-step explanation:

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3 years ago

Read 2 more answers

A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a

USPshnik [31]

Answer:

$Probability = 0.504$

Step-by-step explanation:

Given

$Gems= 35$

$Real = 10$

$Fake = 25$

Required

Determine the probability of selecting two fakes

The probability can be represented as thus: $P(Fake\ and\ Fake)$

Using the following probability formula, we have:

$P(Fake\ and\ Fake) = P(Fake) * P(Fake)$

Each probability is calculated by dividing number of fakes by total number of gems:

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{25-1}{35-1}$

The minus 1 (-1) represent the numbers of fake and total gems left after the first selection

$P(Fake\ and\ Fake) = \frac{25}{35} * \frac{24}{34}$

$P(Fake\ and\ Fake) = \frac{5}{7} * \frac{12}{17}$

$P(Fake\ and\ Fake) = \frac{60}{119}$

$P(Fake\ and\ Fake) = 0.504$

<em>Hence, the required probability is approximately 0.504</em>

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3 years ago