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3 years ago

Hello, help needed. show work please. 55 points!! due today.

Mathematics

1 answer:

MArishka [77]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

x+5

y = ----------------------

x^2 - 2x+1

Since the degree of numerator < degree of denominator ( 1 < 2) there is a horizontal asymptote: y = 0

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Add (13a + 5b) + (a + 5b - 3)

Anni [7]

5 0

3 years ago

Please help thank you.

Mnenie [13.5K]

Answer:

Option D

Step-by-step explanation:

Whenever we take a square root of a number the ± sign is with it like here in the question

$x^2=20\\\\Apply\ square\ root\ on\ both\ sides\\sqrt{x^2}=\sqrt{20} \\\\The\ square\ cancels\ out\ with\ the\ root\x=\sqrt{20}$

And then x = ±4.47 which means x has two values one is +4.47 and the other is -4.47 so Option D is our answer.

7 0

3 years ago

This chart shows the types of ground tissue and their functions.

anyanavicka [17]

Answer:

there is no chart

7 0

3 years ago

PLZ QUICK!!

iragen [17]

Answer:

See attached graph

Step-by-step explanation:

The equation is y-3=(x + 6)

Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.

Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.

y-3 = x+6 -----can be written as : y= x+9

Graph y= x+9 to see the graph and the points that are on the line as attached.

3 0

3 years ago

Read 2 more answers

Plz answer ASAP with work ty!

horsena [70]

Answer: $8\sqrt{6}$

Step-by-step explanation:

$\frac{2^4\sqrt{3}}{\sqrt{2}}$

$2^{\frac{7}{2}}\sqrt{3}$

$2^{\frac{7}{2}}=2^{3+\frac{1}{2}}$

$2^3\cdot \:2^{\frac{1}{2}}$ =

$2^3\sqrt{2}$

= $2^3\sqrt{2}\sqrt{3}$ =

$2^3\sqrt{2\cdot \:3}$

= $2^3\sqrt{6}$

$2^3=8$

Answer- $8\sqrt{6}$

7 0

3 years ago