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3 years ago

Please help meee I can’t do it

Mathematics

2 answers:

choli [55]3 years ago

6 0

D is the answer i’m pretty sure

Bess [88]3 years ago

4 0

A is the correct answer

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EASY MATH!!! GIVING BRAINLIEST!!!

Harman [31]

120 grams half life at 45 days would be 60 then half life of 60 in another 45 days (90 total) should be 30 grams

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3 years ago

Jason is training to run a marathon. His goal for this week is to run a minimum of 42 miles. So far this week, he has already ru

ivanzaharov [21]

Answer:

6m + 18 ≥ 42

Step-by-step explanation:

6m + 18 ≥ 42

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3 years ago

Jeremy's father drives him to school in rush hour traffic in 20 minutes. One day there is no traffic, so his father can drive hi

umka21 [38]

Answer:

Step-by-step explanation:

18/60-12/60= 4 miles

just my guess

6 0

3 years ago

I WILL GIVE BRAINLIEST Answer must be simplified 4x ≤ 12

alina1380 [7]

Answer: x ≤ 3

Step-by-step explanation:

4x ≤ 12

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8 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago