1) 2x+4y=10
3x+5y=14 .
find d2, dx2, and dy
2) Solve the system of equations algebraically and show your work.
2x + 3y = 12
2x - y = 4
3) Which of the ordered pairs (5,5),(5,0) and (-3,2) can be found in the shaded solution area for the system of inequalities below? (The ordered pair must be in the double shaded region or it is not a solution of the system.)
x+2y<6
2x+y > or equal too 9 so yea hoped this helped
X intercept of line a is (-6,0)
x intercept of line b is (1,0)
Answer:
x(x + 8)(x - 8)
Step-by-step explanation:
Given
x³ - 64x ← factor out x from each term
= x(x² - 64) ← x² - 64 is a difference of squares
= x(x + 8)(x - 8) ← in factored form
