2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with
0.0024M KN03 which is mixed with (0.004-0.0024/2)M, it can be 0.0028M, of K2Cr04
Answer:
The anwer is not D the anwer is A
Explanation:
Answer: less humidity, no precipitation and cooler temperatures
Explanation: I just did the assignment
It's not the valences electrons themselves, but the number of valence electrons that determines the chemical properties of an element
