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3 years ago

Pls answer this ASAP thank you

Chemistry

1 answer:

vaieri [72.5K]3 years ago

7 0

Answer:

The anwer is not D the anwer is A

Explanation:

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If a gas has a volume of 750 mL at 25oC, what would the volume of the gas be at 55oC?

blagie [28]

Answer:

The answer to your question is V2 = 825.5 ml

Explanation:

Data

Volume 1 = 750 ml

Temperature 1 = 25°C

Volume 2= ?

Temperature 2 = 55°C

Process

Use the Charles' law to solve this problem

V1/T1 = V2/T2

-Solve for V2

V2 = V1T2 / T1

-Convert temperature to °K

T1 = 25 + 273 = 298°K

T2 = 55 + 273 = 328°K

-Substitution

V2 = (750 x 328) / 298

-Simplification

V2 = 246000 / 298

-Result

V2 = 825.5 ml

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3 years ago

How many moles of gas are in a 30 liter compressed air tank if the

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You are part of a team of scientists and engineers in charge of launching a new spacecraft to Venus. What is one way in which kn

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Answer:

They could see how the spaceship is going to launch and how the trip is going to end up. I hope this helped...!

Explanation:

Chemistry can be used for lots of things, for example, engineering and science such as kinetic energy or mechanical energy.

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4 years ago

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At T = 250 °C the reaction PCl5(g) PCl3(g) + Cl2(g) has an equilibrium constant in terms of pressures Kp = 2.15. (a) Suppose the

Ganezh [65]

Answer:

To the right

Explanation:

Step 1: Given data

Partial pressure of PCl₅ (pPCl₅) = 0.548 atm

Partial pressure of PCl₃ (pCl₃) = 0.780 atm

Partial pressure of Cl₂ (pCl₂) = 0.780 atm

Step 2: Write the balanced equation

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

Step 3: Calculate the pressure reaction quotient

$Q_p = \frac{pPCl_3 \times pCl_2 }{pPCl_5} = \frac{0.780 \times 0.780 }{0.548} =1.11$

Step 4: Determine whether the reaction proceeds to the right or to the left as equilibrium is approached

Since Qp < Kp, the reaction will proceed to the right to attain the equilibrium.

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3 years ago

How many moles of KCIO3 are required to produce 58.3 grams of 02? 2 KCIO3 —> 2 KCI + 3 O2

strojnjashka [21]

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Mole Ratio

Stoichiometry

Analyzing reactions rxn
Using Dimensional Analysis

Explanation:

Step 1: Define

Identify variables

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

Step 2: Identify Conversions

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 58.3 \ g \ O_2(\frac{1 \ mol \ O_2}{32.00 \ g \ O_2})(\frac{2 \ mol \ KClO_3}{3 \ mol \ O_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 1.21458 \ mol \ KClO_3$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃

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3 years ago