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kupik [55]
3 years ago
6

Which conditions are likely to follow the current conditions in the area? Select three responses.

Chemistry
2 answers:
Stels [109]3 years ago
8 0

Answer:

less humidity (B)

no precipitation  (C)

cooler temperatures (E)

Explanation:

Your Welcome :D

Firlakuza [10]3 years ago
6 0

Answer: less humidity, no precipitation and cooler temperatures

Explanation: I just did the assignment

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When hydrogen gas is bubbled into 2-butyne, the product is
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On treatement of 2 -with hydrogen gas and lindlar catalyst, the major product obtained is cis-2butene.

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Why is steam distillation prefered over fractional distillation for the extraction of essencial oils?​
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3 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
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