Answer:
Your question is missing some information.
But in most of the systems, potential energy and kinetic energy are inversely proportional
Explanation:
a)
![k _{sp} = [Ag {}^{ + } ][Cl {}^{ - } ] \\ but \: [Ag {}^{ + } ] = [Cl {}^{ - } ] \\ k _{sp} = [Ag {}^{ + } ] {}^{2} \\ [Ag {}^{ + } ] = \sqrt{k _{sp}} \\ = \sqrt{1.8 \times {10}^{ - 10} } \\ = 1.34 \times {10}^{ - 5} mol {dm}^{ - 3}](https://tex.z-dn.net/?f=k%20_%7Bsp%7D%20%3D%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%5BCl%20%7B%7D%5E%7B%20-%20%7D%20%5D%20%5C%5C%20but%20%5C%3A%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%3D%20%5BCl%20%7B%7D%5E%7B%20-%20%7D%20%5D%20%5C%5C%20k%20_%7Bsp%7D%20%3D%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%7B%7D%5E%7B2%7D%20%20%5C%5C%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%3D%20%20%5Csqrt%7Bk%20_%7Bsp%7D%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B1.8%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%2010%7D%20%7D%20%20%5C%5C%20%20%3D%201.34%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20mol%20%7Bdm%7D%5E%7B%20-%203%7D%20)
b)
It has not reached equilibrium because the silver concentration is not yet equal to the value of Ksp.
c)
Yes it will dissolve in order to establish the equilibrium.
Answer:
1 mole = 6.02x10^23 molecules/particles
Therefore, 3 moles = 3 x 6.02x10^23 = 1.806x10^24
Explanation:
<u>Answer:</u> The balanced chemical equation for the combustion of isooctane is written below.
<u>Explanation:</u>
Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions.
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the combustion of isooctane follows:

By Stoichiometry of the reaction:
1 mole of isooctane reacts with 12 moles of oxygen gas to produce 8 moles of carbon dioxide and 8 moles of water molecule.
Hence, the balanced chemical equation for the combustion of isooctane is written above.
V-?
p≈1g/mL (estimated density of solution)
w=0.02
m(Cli)=12 g
the mass of the solution is:
m=Vp
w=m(Cli)/m=m(Cli)/Vp
the volume of the solution is:
V=m(Cli)/(pw)
V=12g/(1g/mL*0.02)=600 mL