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kupik [55]
3 years ago
6

Which conditions are likely to follow the current conditions in the area? Select three responses.

Chemistry
2 answers:
Stels [109]3 years ago
8 0

Answer:

less humidity (B)

no precipitation  (C)

cooler temperatures (E)

Explanation:

Your Welcome :D

Firlakuza [10]3 years ago
6 0

Answer: less humidity, no precipitation and cooler temperatures

Explanation: I just did the assignment

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How many grams of LiCl are in 1 L of a 0.05 M LiCl solution
STALIN [3.7K]

Answer:

The answer is 2, 12 g of LiCl in 1 L of solution

Explanation:

We calculate the weight of 1 mol of LiCl:

Weight 1 mol LiCl= Weight Li + Weight Cl =6, 94 g + 35, 45 g= 42,39 g/mol

In a 0.05M solution it means that we have 0.05 moles of compound (in this case, LiCl) in 1 liter of solution:

1 mol---------42, 39 g LiCl

0,05mol-----x=(0,05molx 42, 39 g LiCl)/ 1 mol =2, 1195 g LiCl

7 0
4 years ago
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when (Zn^2+)=0.22 M and(
yaroslaw [1]

Answer:

pH = 2.059

Explanation:

At the Cathode:

The reduction reaction is:

2H^+ + 2e^- \to H_2   \ \ \ \mathbf{E^0_{red}= 0.00 \ V}

At the anode:

At oxidation reaction is:

Zn \to Zn^{2+} +2e^-   \ \ \ \mathbf{E^0_{ox} = 0.76 \ V}

The overall equation for the reaction is:

\mathbf{Zn + 2H^+ \to Zn^{2+} + H_2}

The overall cell potential is:

\mathbf{E^0_{cell}= E^0_{ox} + E^0_{red}}

\mathbf{E^0_{cell}= 0.76 \ V +0.00 \ V}

\mathbf{E^0_{cell}= 0.76\ V}

Using the formula for the Nernst equation:

E = E^0 - ( \dfrac{0.0591}{n})log (Q)\\

where;

E = 0.66

(Zn^2+)=0.22 M

Then

0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )

0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )

3.4 = log ( 0.1914) - 2 log [H⁺]

3.4 = -0.7180 - 2 log [H⁺]

3.4 + 0.7180 = - 2 log  [H⁺]

4.118  = - 2  log  [H⁺]

pH = log [H⁺] = 4.118/2

pH = 2.059

8 0
3 years ago
Which diagram shows a voltaic cell?
boyakko [2]
Since you have not included the figures with the diagrams to select the right answer, I am going to explain the main differences that lead you to differentiate electrochemical cells.

There are four important terms needed to identify the electrochemical cells: electrolysis, electrochemical cells, electrolitc cells and voltaic cells.

1) Electrochemical cell: is a device that uses a chemical reaction (redox reaction) to produce electricity or that uses electricity to product a chemical reaction.

2) Electrolysis: is the production of a chemical reaction using electricity.

3) Electroltic cell: is one of the two types of electrochemical cell. It is that in which electricity is used  to produce the chemical reaction, i.e. where electrolysis happens. For example, the decomposition of sodium chloride brines is done in an electrolitic cell.

4) Galvanic cell: is the other type of electrochemical cell. It is that in which chemical reactions (redox reactions) produce electricity. The battery of the car is an example of a galvanic cell.

Here you are asked to identify which diagram shows a voltaic cell.So, you need to lool at:

- a redox reaction is happening

- this redox reaction is producing electricity (not that the electricity is producing the reaction)

Remember that a redox reaction is where some atoms are being reduced (gaining electros) and others are being oxidized (losing electrons).

Tha information will let you to choose the righ diagram.
6 0
3 years ago
What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr (help me please)
ololo11 [35]

<u>Answer:</u> The molarity of KBr solution is 0.605 M

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}       .....(1)

Given values:

Given mass of KBr = 54.0 g

Molar mass of KBr = 119 g/mol

Volume of the solution = 750 mL

Putting values in equation 1, we get:

\text{Molarity of solution}=\frac{54.0\times 1000}{119\times 750}\\\\\text{Molarity of solution}=0.605M

Hence, the molarity of KBr solution is 0.605 M

7 0
3 years ago
In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as
aalyn [17]

Answer:

Single displacement reaction.

Explanation:

Hello!!

In this case, since the reaction between silver nitrate and copper metal is:

2AgNO_3(aq)+Cu(s)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq)

As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.

Therefore, this is a single displacement reaction, because the the lonely copper displaced the silver.

Best regards!

7 0
3 years ago
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