A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
t = 137-w
Step-by-step explanation:
Answer:
Optical axis
Step-by-step explanation:
Optical axis is the rotational symmetry axis of the surfaces.
A line with a certain degree of rotational symmetry is called as the optical axis in an optical system.
It is the straight line that passes through the geometric center of the lens and joins two curvature centers of its surfaces.
It is also called as the principal axis.
Answer:
Step-by-step explanation:
Answer:
The value of a₂₇ is 788
Step-by-step explanation:
a₁₉ = 548
a₃₃ = 968
Now,
a₁₉ = 548 can be written as
a + 18d = 548 ...(1) and
a₃₃ = 968 can be written as
a + 32d = 968 ...(2)
Now, from equation (2) we get,
a + 32d = 968
a + 18d + 14d = 968
548 + 14d = 968 (.°. <u>a + 18d = 548</u>)
14d = 968 - 548
14d = 420
d = 420 ÷ 14
d = 30
Now, for the value of a put the value of d = 30 in equation (1)
a + 18d = 548
a + 18(30) = 548
a + 540 = 548
a = 548 - 540
a = 8
Now, For a₂₇
a₂₇ = a + 26d
a₂₇ = 8 + 26(30)
a₂₇ = 8 + 780
a₂₇ = 788
Thus, The value of a₂₇ is 788
<u>-TheUnknownScientist</u>