No you could have left it as the last but one line or write them separately as
11/18 + √85 / 18 , 11/18 - √85/18
Answer:
Least number of bus require for trip = 5 buses (Approx)
Step-by-step explanation:
Given:
Total number of classes = 9
Number of student in each class = 25
Number of teacher = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
Find:
Least number of bus require for trip
Computation:
Total number of student = 9 × 25
Total number of student = 225
Number of chaperones = 4 × 2
Number of chaperones = 8
Total people = 225 + 8 + 4
Total people = 237
Least number of bus require for trip = Total people / Bus hold
Least number of bus require for trip = 237 / 45
Least number of bus require for trip = 5.266
Least number of bus require for trip = 5 buses (Approx)
216 ft per minute or 3.6 ft per second
515 divided by 216 is 2.38
it takes 2.38 minutes for the specified ant to crawl 515 feet
the answer is D I'm pretty sure!!