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AURORKA [14]
2 years ago
10

How many grams are in 4 moles of Calcium?

Chemistry
2 answers:
faust18 [17]2 years ago
4 0

Answer:

\boxed {\boxed {\sf 160.32 \ g, \ 160 \ g, \ or \ 200 \ g }}

Explanation:

To convert from grams to moles, we must use calcium's molar mass, which can be found on the Periodic Table of Elements.

  • Calcium (Ca) Molar Mass: 40.08 g/mol

Now, we can use the molar mass as a ratio or fraction.

\frac{40.08 \ g \ Ca}{1 \ mol \ Ca}

This fraction can be multiplied by the number of moles, which is 4.

4 \ mol \ Ca * \frac{40.08 \ g \ Ca}{1 \ mol \ Ca}

When we multiply, the moles of calcium will cancel each other out.

4* \frac{40.08 \ g \ Ca}{1}

Since the fraction is over 1, we can just remove the denominator and write a simply multiplication equation.

4* 40.08 \ g \ Ca

160.32 \  g \ Ca

Depending on the teacher's instructions, the answer can be left as is or rounded.

If we round to the technically correct number of significant figures, it would be 1, because the original measurement of 4 moles has 1 sig fig. This would 200 grams, but that's a large amount to round.

We could also round to the nearest whole number. The 3 in the tenth place tells us to leave the whole number as it is. This would be 160 grams.

The answer could be <u>160.32 grams, 160 grams, or 200 grams,</u> depending on rounding and significant figures.

mixer [17]2 years ago
3 0

Answer:

160.32 grams of Ca or 160 if rounded

Explanation:

Multiply moles of Ca by the conversion factor (molar mass of calcium) 40.08 g Ca/ 1 mol Ca, which then allows the cancelation of moles, leaving grams of Ca.

4 mol*40.08g/mol = 160.32 grams of Ca

please give thanks by clicking heart button :)

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All the chemical ingredients to make slime have a mass of 48 grams after we mix all the ingredients together how much mass will
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Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
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To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
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We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
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A 100.0 mL solution containing 0.923 gof maleic acid (MW=116.072 g/mol) is titrated with 0.265 M KOH. Calculate the pH of the so
Vlad1618 [11]

Answer:

pH = 9,57

[M²⁻] = 7,948x10⁻²M

[HM⁻] = 4x10⁻⁵M

[H₂M] = 0M

Explanation:

The moles of maleic acid presents in the solution are:

0,923g×\frac{1mol}{116,072g}=7,952x10⁻³moles of H₂M

60,0mL of 0,265M KOH are:

0,0600L×\frac{0,265mol}{1L}=0,0159 moles of KOH

The reactions of maleic acid (H₂M) and then with HM⁻ are:

H₂M + KOH → HM⁻ + H₂O + K⁺ (1)

HM⁻ + KOH → M²⁻ + H₂O + K⁺ (2)

For a complete transformation of H₂M in HM⁻ there are necessaries 7,952x10⁻³moles of KOH. As the moles of KOH are 0,0159 moles, the restant moles are:

0,0159 - 7,952x10⁻³ = <em>7,948x10⁻³ moles of KOH</em>

By (2), the moles produced of M²⁻ are the same as moles of KOH, <em>7,948x10⁻³  moles, </em>and moles of HM⁻ are:

7,952x10⁻³ -<em> </em>7,948x10⁻³ <em> = 4x10⁻⁶ moles of HM⁻</em>

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] /[HM⁻]

pH = 6,27 + log₁₀ <em>7,948x10⁻³ / 4x10⁻⁶</em>

pH = 9,57

The moles of M²⁻ are 7,948x10⁻³  and volume of the solution is 0,1000L,

[M²⁻] = 7,948x10⁻²M

Moles of HM⁻ are 4x10⁻⁶:

[HM⁻] = 4x10⁻⁵M

And there is not H₂M:

[H₂M] = 0M

I hope it helps!

8 0
3 years ago
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