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AURORKA [14]
3 years ago
10

How many grams are in 4 moles of Calcium?

Chemistry
2 answers:
faust18 [17]3 years ago
4 0

Answer:

\boxed {\boxed {\sf 160.32 \ g, \ 160 \ g, \ or \ 200 \ g }}

Explanation:

To convert from grams to moles, we must use calcium's molar mass, which can be found on the Periodic Table of Elements.

  • Calcium (Ca) Molar Mass: 40.08 g/mol

Now, we can use the molar mass as a ratio or fraction.

\frac{40.08 \ g \ Ca}{1 \ mol \ Ca}

This fraction can be multiplied by the number of moles, which is 4.

4 \ mol \ Ca * \frac{40.08 \ g \ Ca}{1 \ mol \ Ca}

When we multiply, the moles of calcium will cancel each other out.

4* \frac{40.08 \ g \ Ca}{1}

Since the fraction is over 1, we can just remove the denominator and write a simply multiplication equation.

4* 40.08 \ g \ Ca

160.32 \  g \ Ca

Depending on the teacher's instructions, the answer can be left as is or rounded.

If we round to the technically correct number of significant figures, it would be 1, because the original measurement of 4 moles has 1 sig fig. This would 200 grams, but that's a large amount to round.

We could also round to the nearest whole number. The 3 in the tenth place tells us to leave the whole number as it is. This would be 160 grams.

The answer could be <u>160.32 grams, 160 grams, or 200 grams,</u> depending on rounding and significant figures.

mixer [17]3 years ago
3 0

Answer:

160.32 grams of Ca or 160 if rounded

Explanation:

Multiply moles of Ca by the conversion factor (molar mass of calcium) 40.08 g Ca/ 1 mol Ca, which then allows the cancelation of moles, leaving grams of Ca.

4 mol*40.08g/mol = 160.32 grams of Ca

please give thanks by clicking heart button :)

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Answer:

\boxed{\text{163.3 L}}

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law:

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = ?;            T₁ =    450 K

V₂ = 103.4 L; T₂ = 284.9 K

Calculation:

\dfrac{ V_{1}}{450} = \dfrac{ 103.4}{284.9}\\\\{ V_{1}} = 450 \times \dfrac{103.4}{284.9}\\\\ = \textbf{163.3 L}\\\text{The original volume of the helium was $\boxed{\textbf{163.3 L}}$}

5 0
3 years ago
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Calculate the number of mg of Mn2+ left
soldi70 [24.7K]

Answer:

1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

Explanation:

The reaction that takes place is:

Mn⁺² + S⁻² ⇄ MnS(s)  

ksp = [Mn⁺²] [S⁻²]

If the pksp of MnS is 13.500, then the ksp is:

ksp=10^{-13.500}=3.1623*10^{-14}

From the problem we know that [S⁻²] = 0.0900 M

We use the ksp to calculate [Mn⁺²]:

3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M

[Mn⁺²] = 3.514 * 10⁻¹³ M.

Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:

3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.

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3 years ago
What is the mass of sodium (Na) in 50 grams of table salt (NaCl)? Show your work.
beks73 [17]

Answer:

The amount of sodium in this sample = 32.4 grams

Explanation:

Mass of Sodium = 23 g/mol

Mass of Chlorine = 35.5 g/mol

Mass of NaCl = 35.5 g/mol

Fraction of Na in NaCl = \frac{23}{35.5}

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We are given a sample of 50 grams of sodium chloride.

The amount of sodium in this sample = Amount of sodium in 1 gram sample \times weight of sample

The amount of sodium in this sample = 0.648 \times 50

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