Question is incomplete, complete question is;
A 34.8 mL solution of 
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of 
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of (aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.044 M is the molarity of (aq).
5 bromo 1.1.1 -trichloro -5 ethyl 2.3 dimethyl heptane
HELPPPPPPPPPPPPPPPPPPPPPPPf it is a good idea to
Heat speeds up chemical reaction.The less water in the desert, which is a crucial element in performing chemical weathering...
Hope this helps..
Answer:
Yes N3- is correct ion notation. The N element is in the form N2 . Also it is a triple covalent bond and so this correct
