The magnetic effect of a magnet is strongest at ____

Analyze the map. How would the temperature on the east coast of South America (near Brazil) differ from the west coast of South

hjlf

Answer: Uruguay on north on the Atlantic side, Chile and north on the Pacific side. The higher up you go the warmer, so Brazil, Ecuador, and Colombia will be the warmest especially in terms of water temperature.

5 0

3 years ago

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Which solute would be more effective at lowering the freezing point of water: MgCl2 and KNO3? Explain.

Phantasy [73]

Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

(3) NaCl:

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃

4 0

3 years ago

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What does a neutralization reaction produce?

algol13

Answer:

hope this help....

Explanation:

Neutralization is the reaction of an acid and a base, which forms water and a salt. Net ionic equations for neutralization reactions may include solid acids, solid bases, solid salts, and water.

7 0

3 years ago

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Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c

KiRa [710]

Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps

Initial x

React s

Eq x - s s 2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s = ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

3 0

3 years ago

What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The

pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Mass of isotope 1 = 34.97 amu

Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

$\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]$

$\text{Average atomic mass of element}=32.37amu$

Therefore, the average atomic mass of chlorine is, 32.37 amu

8 0

3 years ago

The magnetic effect of a magnet is strongest at _____.