<u>Answer:</u> The concentration of 
ions is 0.10 M and that of 
ions is 0.30 M
<u>Explanation:</u>
We are given:
Concentration of 
= 0.10 M
The chemical equation for the ionization of aluminium bromide follows:
1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions
So, concentration of aluminium ions = 0.10 M
Concentration of bromide ions = ![[(3\times 0.1)]=0.3M](https://tex.z-dn.net/?f=%5B%283%5Ctimes%200.1%29%5D%3D0.3M)
Hence, the concentration of ions is 0.10 M and that of ions is 0.30 M
Answer: The sample of ammonium carbonate contains
0.560 mol NH
4
Explanation:The chemical formula for ammonium carbonate is
(
NH
4
)
2
CO
3
. The formula indicates that in one mole of ammonium carbonate, there are two moles of ammonium ions,
NH
4
HBr reacts with LiOH and forms LiBr and H₂O as the products. The balanced reaction is
LiOH(aq) + HBr(aq) → LiBr(aq) + H₂O(l)
Molarity (M) = moles of solute (mol) / volume of the solution (L)
Molarity of LiOH = 0.205 M
Volume of LiOH = 29.15 mL = 29.15 x 10⁻³ L
Hence,
moles of LiOH = molarity x volume of the solution
= 0.205 M x 29.15 x 10⁻³ L
= 5.97575 x 10⁻³ mol
The stoichiometric ratio between LiOH and HBr is 1 : 1.
Hence,
moles of HBr in 25.0 mL = moles of LiOH added
= 5.97575 x 10⁻³ mol
Hence, molarity of HBr = 5.97575 x 10⁻³ mol / 25.00 x 10⁻³ L
= 0.23903 M
≈ 0.239 M
Hence, the molarity of the HBr is 0.239 M.
