Which property is the same for a 50 mL sample of liquid water and a 100 mL sample of liquid water?
1 answer:
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Explanation:
Upon dissolution of KCl heat is generated and temperature of the solution raises.
Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.
= 4.31 kJ
or, = 4310 J (as 1 kJ = 1000 J)
Mass of solution will be the sum of mass of water and mass of KCl.
Mass of Solution = mass of water + (no. of moles of KCl × molar mass)
= 200 g +
= 200 g + 13.625 g
= 213.625 g
Relation between heat, mass and change in temperature is as follows.
Q =
where, C = specific heat of water =
Therefore, putting the given values into the above formula as follows.
Q =
4310 J =
Thus, we can conclude that rise in temperature will be .