New perimeter is 4040-2424= 1616
original, let x and y be length and width
2x + 2y = 4040
new
2x/2 +2y/3 = 1616
x +2y/3 = 1616
x = 1616 - 2y/3
sub this x value into first eq
2(1616-2y/3) + 2y = 4040
3232 - 4y/3 + 2 = 4040
put like terms together
-4y/3+2y=4040-3232
2y/3=808
multiply both sides by 3
2y = 2424
divide both sides by 2
y=1212
sub this y value into any eq. i chose eq 1
2x+2(1212)= 4040
2x = 4040 - 2(1212)
2x = 1616
x = 808
so the length is 808 and the width is 1212
<u>Given:</u>
The two equations are
and 
We need to solve the equations using elimination method.
<u>Elimination method:</u>
Let us multiply the equation
by 5, we get;
---------(1)
Now, multiplying the equation
by -2, we get;
--------(2)
Adding equations (1) and (2), we have;


Thus, the value of y is 3.
Substituting
in the equation
, we have;




Thus, the value of x is 4.
Hence, the solution of the system of equations is (4,3)
Therefore, Option A is the correct answer.
Answer:
x = - 
Step-by-step explanation:
the equation of a circle centred at the origin is
x² + y² = r² ( r is the radius )
The radius of a unit circle is r = 1
substitute (x, -
) into the equation and solve for x
x² + (-
)² = 1²
x² +
= 1 ( subtract
from both sides )
x² = 1 -
=
( take square root of both sides )
x = ±
= ± 
since the point is in the 3rd quadrant then x < 0
x = - 
Answer:
1. about 7.87 feet away
2. About 8.37 yds
Step-by-step explanation:
1. a^2+b^2=c^2
so 25+37= C^2
= 62
Square root of 62 = 7.87400787401
(About 7.87 ft away)
2. 40+30 = C^2
Square root of 70 = 8.36660026534
About 8.37