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mezya [45]
3 years ago
9

Investigate and explain that when a force is applied to an object but it does not move, it is because another opposing force is

being applied by something in the environment so that the forces are balanced.
The diagram below shows a box lying on a wedge. Two opposite forces are acting on the box. (1 point)

Force 1 acting downward and Force 2 acting upward on a square box lying on a wedge.

If the box is stationary, which of the following is true about force 1 and force 2?
1. Force 1 Force 2 Comparison of Forces
Gravity Friction Force 1 is stronger than Force 2
2. Force 1 Force 2 Comparison of Forces
Friction Gravity Force 2 is stronger than Force 1
3. Force 1 Force 2 Comparison of Forces
Gravity Friction Force 1 is equal to Force 2
4. Force 1 Force 2 Comparison of Forces
Friction Gravity Force 1 is equal to Force 2
Chemistry
2 answers:
N76 [4]3 years ago
5 0

Answer:

4. Force 1 Force 2 Comparison of Forces

Friction Gravity Force 1 is equal to Force 2

Explanation:

oksian1 [2.3K]3 years ago
4 0
The answer is number 4
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The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons.
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Answer:

The four quantum number for each electron will be:

1s^{2}

n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2s^{2}

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2p^{6}

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Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

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Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

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The two electrons in each orbital will have either plus half or minus half spin quantum number

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If the p-side has a higher doping concentration, explain how to keep tuning to the same radio channel?
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A balance in the intrinsic concentration helps in tuning to the same radio channel.

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