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Ymorist [56]
3 years ago
12

. Which of the following is NOT the basic patterns of crystalline structure?

Chemistry
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

c) Hexagonal close packed

Explanation:

The fact that a material is crystalline, amorphous or semicrystalline defines some of its properties. For example, if a material had the option of being crystalline or amorphous, it would be observed that in the crystalline state the density of the material would be greater in the amorphous state. This is because because of the order that the atoms follow in the crystalline material, it is possible to place more atoms in the same physical volume. When there are more atoms there is more mass in the same volume so the density is higher than when the material is amorphous.

The different crystalline structures are the following:

Simple cubic structures: the unit cell is a common edge cube, with a defined network point in each of its vertices.

Cubic structure centered on the body: the unit cell is a cube with a common edge. It has a defined network point in each of its vertices and a defined network point in the geometric center of the cube. INCLUDES a)

Cubic structure centered on the face: the unit cell is a cube with a common edge. It has a defined network point in each of its vertices and a defined network point in the geometric center of each of its faces. INCLUDES b) and d)

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Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as
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Answer:

0.100 m AlCl3  will have the highest boiling point

Explanation:

Step 1: Data given

The molal boiling point elevation constant for water is 0.51°C/m

Since those are all  aqueous solutions, the have the same molal boiling point elevation constant

Step 2:

0.100 m C6H12O6

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr = 1

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT = 1 * 0.51 * 0.100

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0.100 m NaCl

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Na+ + Cl- = 2

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =2 * 0.51 * 0.100

ΔT = 0.102 °C

0.100 m AlCl3

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Al^3+ + 3Cl- = 4

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =4 * 0.51 * 0.100

ΔT = 0.204 °C

0.100 m MgCl2

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Mg^2+ +2Cl- = 3

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =3 * 0.51 * 0.100

ΔT = 0.153 °C

0.100 m AlCl3  will have the highest boiling point

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