Answer:
The specific heat of zinc is 0.361 J/g°C
Explanation:
<u>Step 1:</u> Data given
44.0 J needed
Mass of solid zinc = 10.6 grams
Initial temperature = 24.9 °C
Final temperature = 36.4 °C
<u>Step 2</u>: Calculate the specific heat of zinc
Q = m*c*ΔT
⇒ with Q = heat (in Joule) = 44.0 J
⇒ with m = the mass of the solid zinc = 10.6 grams
⇒ with c = the specific heat of the zinc = TO BE DETERMINED
⇒ with ΔT = The change in temperature = T2-T1 = 36.4 °C - 24.9 °C = 11.5 °C
44.0 J = 10.6 grams * c * 11.5°C
c = 44.0 J / (10.6g * 11.5 °C)
c = 0.361 J/g°C
The specific heat of zinc is 0.361 J/g°C
Answer:
2Mg + O2 → 2MgO
Explanation:
In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.
Rubber it's not a conductor
I believe the answer is <span>can be elements or compounds
In this case, elements in the decomposition reaction is the substance that cannot be separated into simpler substances.
Compounds, technically act as a reactant in the decomposition reaction, but since the reaction breakdown one substance into two or more, sometimes it exists in the product.</span>
