Answer:
the answer is B the image will be in quadrant III
Step-by-step explanation:
Write the equation of a line that is parallel to y=-5/4x + 7
Any line parallel to the given line will have the same slope. In an equation presented in the y-intercept form, the slope is always the coefficient of "x". In this case, the slope is -5/4 (meaning the next point is down 5, and 4 to the right).
Our equation so far looks like this: y = -5/4x + b
"b" represents the y-intercept. To solve for be, we will need to substitute values into x and y. The next piece of information it gives us is one of the points, or solutions, of the line. This means that since this point is on the line, we can use its x and y values to substitute.
x = -4
y= 1
y = -5/4x + b
1 = -5/4(-4) + b
1 = 5 + b
-4 = b
Final Answer: y = -(5/4)x -4
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we are supposed to find
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.
The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.
In a parallelogram The opposite angles and opposite sides are always equal.
Hence the correct option is
The diagonals are congruent.
Answer:
x + 5
Step-by-step explanation:
A = LW
W = A/L
W = (x^2 + 16x + 55)/(x + 11)
W = [(x + 11)(x + 5)]/(x + 11)
W = x + 5
