How to convert 15 cm to mm

24. If Jenna spent 30 hours on the computer this week. how much total time did she spend on

Verdich [7]

Option B) 3 hours is the time spent by Jenna on the e-mail this week.

Step-by-step explanation:

Jenna spent 30 hours on the computer this week.

The amount of time she spends on computer to work on various fields in given in the pie-chart.

This 30 hours represents her 100% work on computer.

From the figure shown,

She spent 10% of her total work on e-mail.

Therefore, 10% of 30 is the work done in hours by her on e-mail.

⇒ (10/100) × 30

⇒ 0.1 × 30

⇒ 3 hours

∴ Option B) 3 hours is the time spent by Jenna on the e-mail this week.

7 0

3 years ago

Taryn is shopping for a Christmas tree. At Home Depot the one she likes is $149.00 and she has a 15% off coupon. At Lowe's the o

Vitek1552 [10]

Answer:

Step-by-step explanation:

At home depot

Price of Christmas tree = $149.00

Discount = 15%

Amount discounted = 15% of $149

Amount discounted = 15/100 * $149

Amount discounted = 15 * 1.49

Amount discounted = $22.35

Amount she paid = $149-$22.35

Amount she paid = $126.65

At Lowe's:

Price of Christmas tree = $175.00

Discount = 260%

Amount discounted = 20% of $175

Amount discounted = 20/100 * $175

Amount discounted = 0.2 * 175

Amount discounted = $35

Amount she paid = $175-$35

Amount she paid at Lowe's = $140

From the prices above, it can be seen that Home Depot has a better deal since the price after removing discount is lower than that of Lowe's.

Amount she will save will be $140 - $126.65 = $13.35

6 0

3 years ago

Write a real world problem that you would represent with the equation 4x+5=37.

umka2103 [35]

If there were 37 apples. One of your friends took 5 apples. You divided the leftover apples and gave it to your four friends. How many apples did each of the four friends get?

x=8
37-5=32
32/4=8.

8 0

3 years ago

Use the information in the diagram to determine the height of the tree. The diagram is not a scale

dusya [7]

In the given diagram, we can note that the tree divides the hypotenuse of the triangle as well as the side where the tree is based into halves.

In a triangle, when a line is drawn joining between the midpoints of two sides, this line is always parallel to the third side and equals half its length.

Applying this concept to the given diagram here, we will find that the tree is joining the midpoints of two sides of the triangle. this means that the tree is parallel to the building and the height of the tree is half the height of the building.

Therefore:
height of tree = 0.5 * 120 = 60 ft

6 0

3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

How to convert 15 cm to mm​

How to convert 15 cm to mm