<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
18 is the length . Your welcome :)
Answer:
D. 180 degres
Step-by-step explanation:
Answer:
x = 2
Step-by-step explanation:
First, distribute 6 to all terms within the parenthesis.
6(2x + 3) = 12x + 18
Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
12x + 18 = 42
First, subtract 18 from both sides.
12x + 18 (-18) = 42 (-18)
12x = 24
Isolate the variable x. Divide 12 from both sides.
(12x)/12 = (24)/12
x = 24/12
x = 2
2 is your answer for x.
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