Answer:
Hope this helps
Step-by-step explanation:
a) <e and <c
b) <c and <b
c) <c and <a
d) <c and <b, <c and <d, <d and <e, <e and <a, <a and <b
e) c = 30, a = 90, b= 60, e= 30, d= 150
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75
The angle is α = arccos(-0.8) ≈ 143.13°
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For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.
For a better understanding of the solution provided here please find the diagram attached.
Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.
Thus, if, for example, the end coordinates of a line segment are 
and 
then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:
Thus for our question the endpoints are 
and 
and hence the midpoint will be:
Thus, Option C is the correct option.
X+10=15
Isolate x by subtracting 10 from both sides
x+10-10=15-10
x=5
Final answer: B
Check by plugging the value in
5+10=15
True
