The pay section I hope that helped a little bit
Answer:
speed=d/t
let him cover x distance while walking
running d=4.5-x
s1=x/0.5 km/hr....(1)
s2=4.5-x//5/12.....(2)
atq.....s2=2+s1
s1=2x
s2=54-12x/5
by eqn 1 and 2
s1+s2=2x+54-12x/5
putting value of s2
s1+2+s1=2x+54-12x/5....taking LCM =5
10s1+10= 10x+54-12x
as s1=2x
10s1+10= -2x+54
10s1+10=-s1+54
11s1=44
speed when walking=4km/hr
Answer:
When x = 10, they will both be y = 60
(10, 60)
Step-by-step explanation:
2(10) + 40 = 60
4(10) + 20 = 60
Answer:
40" by 50"
Step-by-step explanation:
closest estimate
Answer:
Is the w2, w(2) or

?
If it's w(2) the answer is -4--8+1=-4+8+1=5
if it's w^2 then the answer would be 4--8+1=4+8+1=13