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Vadim26 [7]
3 years ago
11

The following frequency distribution presents the five most frequent reasons for hospital admissions in U.S. community hospitals

in a recent year.
Reason Frequency (in thousands)
Congestive heart failure    990
Coronary atherosclerosis 1400
Heart attack   744
Infant birth 3800

Required:
a. Construct a frequency bar graph.
b. Construct a relative frequency distribution.
c. Construct a relative frequency bar graph.
d. Construct a relative frequency Pareto chart.
Mathematics
1 answer:
zmey [24]3 years ago
7 0

Answer:

See Explanation

Step-by-step explanation:

Given

Reason \to Frequency

Congestive\ heart\ failure   \to 990

Coronary\ atherosclerosis\to 1400

Heart\ attack  \to 744

Infant\ birth\to 3800

Solving (a): Frequency bar graph

To do this, we simply plot the reasons (on the x-axis) against the frequency (on the y-axis).

<em>See attachment</em>

Solving (b): Relative frequency distribution

The relative frequency is calculated as:

RF = \frac{F}{Total}

Where

Total = 990+1400+744+3800

Total = 6934

So, we have:

Congestive\ heart\ failure \to \frac{990}{6934}  = 0.1427

Coronary\ atherosclerosis\to \frac{1400}{6934}  = 0.2019

Heart\ attack  \to \frac{744}{6934} = 0.1073

Infant\ birth\to \frac{3800}{6934}  = 0.5481

So, the relative distribution is:

Reason \to Frequency \to Relative\ Frequency

Congestive\ heart\ failure   \to 990 \to 0.1427

Coronary\ atherosclerosis\to 1400 \to 0.2019

Heart\ attack  \to 744 \to 0.1073

Infant\ birth\to 3800 \to 0.5481

Solving (c): Relative frequency bar graph

To do this, we simply plot the reasons (on the x-axis) against the relative frequency (on the y-axis).

<em>See attachment</em>

Solving (d): Relative frequency Pareto chart

First, calculate the cumulative relative frequency

This is done by adding up the previous relative frequency,

So, we have:

Reason \to Relative\ Frequency \to Cumulative

Congestive\ heart\ failure   \to 0.1427 \to 0.1427

Coronary\ atherosclerosis \to 0.2019 \to 0.2019+0.1427=0.3446

Heart\ attack  \to 0.1073\to 0.3446+0.1073 = 0.4519

Infant\ birth \to  0.5481 \to 0.5481+4519 =1

So, we have:

Reason \to Relative\ Frequency \to Cumulative

Congestive\ heart\ failure   \to 0.1427 \to 0.1427

Coronary\ atherosclerosis \to 0.2019 \to 0.3446

Heart\ attack  \to 0.1073\to 0.4519

Infant\ birth \to  0.5481 \to 1

Next, we simply plot the reasons (on the x-axis) against the cumulative relative frequency (on the right) and the left of the Pareto chart.

<em>See attachment</em>

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