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3 years ago

Find the value of x, pls show work so i know how to solve it :)))

Mathematics

2 answers:

Katena32 [7]3 years ago

7 0

Answer:

x = 71°

Step-by-step explanation:

Since the 2 legs are congruent then the triangle is isosceles and the 2 base angles are congruent, that is

x = 71°

RideAnS [48]3 years ago

4 0

Answer:

x=71

Step-by-step explanation:

(Base angle of an isosceles triangle)

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Please help asap! i need to find the missing coordinate

Harrizon [31]

Answer:

8 or 32

Step-by-step explanation:

So we are given two coordinates and the length of the segment formed by those coordinates.

To find the unknown coordinate, we can use the distance formula. Let the unknown value be n:

Let's let (-2,n) be x₁ and y₁ and let (-7,20) be x₂ and y₂.

The distance formula is given by the formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-2,n) for x₁ and y₁ and (-7,20) for x₂ and y₂. Also, since we already know that the length is 13, substitute it for d. Thus:

$(13)=\sqrt{((-7)-(-2))^2+((20)-(n))^2}$

Do the operations within the parentheses:

$13=\sqrt{(-7+2)^2+(20-n)^2}\\13=\sqrt{(-5)^2+(20-n)^2}$

Now, square both sides to take out the square root:

$(13)^2=(\sqrt{(-5)^2+(20-n)^2})^2$

Simplify:

$169=(-5)^2+(20-n)^2$

Square (-5):

$169=25+(20-n)^2$

Subtract 25 from both sides. The right cancels:

$(169)-25=(25+(20-n)^2)-25\\144=(20-n)^2$

Now, take the square root of both sides.

$\pm\sqrt{144}=\sqrt{(20-n)^2}$

Simplify:

$\pm12=(20-n)$

So, we have two solutions:

$(12=20-n)\text { or }(-12=20-n)$

On the left, subtract 20. On the right, also subtract 20:

$(-8=-n)\text { or }(-32=-n)$

Divide both sides by -1:

$(n=8)\text{ or } (n=32)$

So, our two possible answers are 8 or 32.

5 0

3 years ago

If the length of diagonal of a square is 4√2 cm, find it's length, perimeter and area.

Sonbull [250]

Answer:

As Per Provided Information

Length of diagonal of square is 4√2 cm

We have been asked to find the length , perimeter and area of square .

First let's calculate the side of square .

Using Formulae

$\boxed{\bf \:Diagonal_{(Square)} \: = side \sqrt{2}}$

On substituting the value in above formula we obtain

$\qquad\longrightarrow\sf \:4 \sqrt{2} = side \sqrt{2} \\ \\ \\ \qquad\longrightarrow\sf \:4 \cancel{\sqrt{2}} = side \cancel{ \sqrt{2}} \\ \\ \\ \qquad\longrightarrow\sf \:side \: = 4 \: cm$

Therefore,

Length of its side is 4 cm.

Finding the perimeter of square.

$\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}$

Substituting the value we obtain

$\qquad\longrightarrow\sf \:Perimeter_{(Square)} \: = 4 \times 4 \\ \\ \\ \qquad\longrightarrow\sf \:Perimeter_{(Square)} = 16 \: cm$

Therefore,

Perimeter of square is 16 cm .

Finding the area of square .

$\boxed{\bf \: Area_{(Square)} = {side}^{2}}$

Substituting the value we get

$\qquad\longrightarrow\sf \:Area_{(Square)} \: = {4}^{2} \\ \\ \\ \qquad\longrightarrow\sf \:Area_{(Square)} = 16 \: {cm}^{2}$

Therefore,

Area of square is 16 cm².

3 0

2 years ago

Which of these is a correct step in constructing congruent angles?

Marrrta [24]

Answer:

if not mistaken is use a compass and draw an arc across both the legs of the given angle

LET ME KNOW IF HELPED

8 0

3 years ago

What is the volume in cubic centimeters of a rectangular prism that has a length of 6.2 centimeters, a width of 3.5 centimeters,

Rufina [12.5K]

The length is 6.2
the width is 3.5
the height is 10
So the volume =217cm^3

I hope this help

5 0

3 years ago

Read 2 more answers

Iv) 6x+3y=6xy 2x + 4y= 5xy

Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5 - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

$y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}$

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0

3 years ago