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hichkok12 [17]
3 years ago
6

A random sample of 36 students at a community college showed an average age of 25 years. assume the ages of all students at the

college are normally distributed with a standard deviation of 1.8 years. the 98% confidence interval for the average age of all students at this college is
Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
<span>24.301 to 25.699 hopw this helps

</span>
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An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa
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Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

  • M is the mean of five successive weightings (3.150)
  • ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)
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Using the numbers 95% confidence interval estimate of the true weight is:

3.150±\frac{2.776*0.1}{\sqrt{5} }≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150±\frac{4.604*0.1}{\sqrt{5} }≈3.150±0.206

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3 years ago
Given: 5x + 3 &gt; 4x + 7. Choose the graph of the solution set.
riadik2000 [5.3K]
Let's solve your inequality step-by-step.

<span><span><span>5x</span>+3</span>><span><span>4x</span>+7

</span></span>Step 1: Subtract 4x from both sides.

<span><span><span><span>5x</span>+3</span>−<span>4x</span></span>><span><span><span>4x</span>+7</span>−<span>4x

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</span>Step 2: Subtract 3 from both sides.

<span><span><span>x+3</span>−3</span>><span>7−3

</span></span><span>x>4

</span>Answer:

<span>x><span>4</span></span>
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