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a_sh-v [17]
3 years ago
13

Fimd the medium.of given data ? 5,19,8,11,7,6,17,11,6,10​

Mathematics
1 answer:
dybincka [34]3 years ago
5 0
The median of the given data is nine!!
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Donald has x twenty dollar bills and one ten dollar bill how much money does Donald have
Paha777 [63]
In equation form that would be X20+10. He has X amount of 20 dollar bills, then a 10 dollar bill. We have to multiply X by 20 first, then add that to 10.

~Deceptiøn
5 0
3 years ago
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A yield sign is an equilateral triangle with a side length of 36in what is the height h of the sign? Round to the nearest in
AlladinOne [14]
The height is 31.17691454 in. 
5 0
3 years ago
X = 28+3(6) what would be the answer​
Pani-rosa [81]

Answer:

X = 28+3(6)

X = 28 +18

<u>X = 46</u>

Thus, the <u>value of X </u>will be <u>46</u>.

Hope it helps.

5 0
3 years ago
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Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
Log4 216-log4 8 =log4 x
tekilochka [14]
216/8= 27. X= 27. Subtract you divide
4 0
3 years ago
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