9+3=12
30+20=50
300+100=400
Then add.
12+50+400=462
<span>So 339+123=462</span>
Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
Step-by-step explanation:
Explanation:
Because
(2,6) is in the function, we can plug
6 as y
and
2 as x.
From that we get
6=a(2−1)2+k
6=a+k
Same for the next point:
12=a(3−1)2+k
12=22a+k
12=4a+k
Now we have this system of equations to solve:
a+k=6
4a+k=12
Solving it leads to the conclusion that
a=2,k=4 .
Answer:
B is the correct answer.
Step-by-step explanation:
graph attached below, with red as the parent function (f(x)=3^x) and blue as the change (f(x)=3^x-8).
45.3297 rounded to the nearest tenth is 45.3
3 is in the tenths place, so you look at the number to the right of it. If that number is 5 or more, you round up. If the number is 4 or less, you round down. So you round 45.3297 down to 45.3